Answer key for the ISRO Paper 2011 (SET A) :
1. D
2. A
3. D
4.
5.
6. B
7.C
8. D
9. B
10.D
11.D
12.D
13.D
14.C
15.A
16.B
17.D
18.A
19.D
20.C
21.C
22.C
23.C
24.A
25.C
26.A
27.C
28.A
29.D
30.C
31.D
32.B
33.A
34.C
35.B
36.B
37.C
38.
39.B
40.A
41.B
42.B
43.C
44.A
45.
46.C
47.B
48.C
49.
50.C
51.C
52.
53.A
54.C
55.A
56.A
57.C
58.
59.
60.B
61.B
62.D
63.
64.D
65.A
66.C
67.B
68.B
69.C
70.C
71.B
72.C
73.A
74.B
75.
76.B
77.D
78.A
79.D
80.B
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1. D
2. A
3. D
4.
5.
6. B
7.C
8. D
9. B
10.D
11.D
12.D
13.D
14.C
15.A
16.B
17.D
18.A
19.D
20.C
21.C
22.C
23.C
24.A
25.C
26.A
27.C
28.A
29.D
30.C
31.D
32.B
33.A
34.C
35.B
36.B
37.C
38.
39.B
40.A
41.B
42.B
43.C
44.A
45.
46.C
47.B
48.C
49.
50.C
51.C
52.
53.A
54.C
55.A
56.A
57.C
58.
59.
60.B
61.B
62.D
63.
64.D
65.A
66.C
67.B
68.B
69.C
70.C
71.B
72.C
73.A
74.B
75.
76.B
77.D
78.A
79.D
80.B
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7th is B. because statements inside process statement are sequential.
ReplyDeletewhy is the answer a for question no.15
ReplyDeleteMayank,
DeleteI have considered that examiner is looking for minimum transmission bandwidth which is bw/2.
14.4/2 so ans is A.
thanku so much sir can you provide 2010 and 2009 key also it will help me alottt
ReplyDeleteQ. 15 answer is D. Successive Approximation type because it has almost same conversion time for each bit. So 12 bit ADC will take almost 14 us time.
ReplyDeleteQn NO: 4 Option B.1.29um . lamda=((2*pi*a)/2.405)*(sqrt((n1^2-n2^2)))
ReplyDeleteWhy u left blank in so many questions.. ?
ReplyDelete51-D
ReplyDeleteans 1 A
ReplyDelete